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Y
Y ou
10
v Y
s O
v O
s Y
y
Q
q
10
Z
25
X
Figure 11.5.
The relative values are
relative location of object:
q
y
=
15 i km
relative velocity of object:
3 j kmh 1
s O ˆ
v O
s Y ˆ
v Y =−
+
4 i
Therefore, from the relative velocity, the relative speed is
5 kmh 1
4 2
s O ˆ
v O
s Y ˆ
v Y =
+
3 2
=
and the relative direction is
4
5 i
3
5 j km
v O −ˆ
ˆ
v Y =−
+
Therefore,
5 j
4
5 i
3
+
·
15 i
24 kmh 1
12
5 =
t C =
=
5
Substituting 24 h in Eq. (11.10) gives
5 j
12
5 ×
4
5 i
3
d
=
15 i
+
5
×
+
5 j
48
5 i
36
d
=
15 i
+
5 j =
27
5 i
36
d
=
+
9 km
Thus, the close encounter occurs 24 hours after the reference time, and the object is 9 km from
you.
 
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