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and
N =
N
×
N
A
then
N
×
D
=
N
A
Furthermore,
N
×
D
=
N
A
(10.14)
But as N is perpendicular to D , we have
sin 90 =
N
×
D
=
N
D
N
D
(10.15)
Equations (10.14) and (10.15) imply that
D
=
A
.
N is rotated , as shown in Fig. 10.8(a), where
=
D
=
A
tan
N
N
or
F
v
P
u
F
u
P
v
tan 1
=
P
u ×
P
v
So this allows us to develop a perturbation strategy based upon rotations, rather than offsets.
Now let's illustrate the above analysis with an example. To keep the mathematics simple, let's
use a cylinder as the bivariate vector function, as shown in Fig. 10.9.
Y
v
v
Z
P (u , v)
u
u
X
Figure 10.9.
For instance, if the radius and the height of the cylinder equal 1 and uv
02, then
the x component is given by cos u,
the y component is given by v,
the z component is given by
sinu,
 
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