Graphics Reference
In-Depth Information
x R 1 z R
x S 1 z S
x T 1 z T
z S
z R x S
x R
=
=
b
or b
z T
z R x T
x R
x R y R 1
x S y S 1
x T y T 1
x S
x R y S
y R
c
=
or c
=
x T
x R y T
y R
d
=
ax R +
by R +
cz R
4.5 A plane perpendicular to a line and passing through a point
Although there are an infinite number of planes perpendicular to a given line, simply by defining
a point that lies on a plane enables us to fix a unique plane. In this section we derive a formula
that defines the Cartesian form of the plane equation using a line and a point. The line represents
a vector perpendicular to a plane, while the point identifies a specific plane in space.
Y
P
n
p
Q
q
Z
X
Figure 4.5.
With reference to Fig. 4.5, let the plane equation be
ax
+
by
+
cz
=
d
and the line direction vector be
=
+
+
n
a i
b j
c k
and the specified point on the plane be
Q x Q y Q z Q
 
Search WWH ::




Custom Search