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namely:
c 0
c 0
5
8 c 0 ¼ c 0 2 Z
5
16
« w ¼ 2
2 Zc 0
þ
ð 4
:
27 Þ
In (4.26), the first term on the right is the one-electron matrix element
already found for H, while the second is the two-electron repulsion
integral between the two spherical 1s charge distributions written in
charge density notation:
ðð d r 1 d r 2 ½ 1s ðr 2 Þ 1s ðr 2 Þ
r 12
h 1s 1 1s 2 j r 1
1s ðr 1 Þ 1 s ðr 1 Þ
¼ ð 1s 2
j 1s 2
12 j 1s 1 1s 2
½
Þ
ð 4
:
28 Þ
This new two-electron integral is evaluated in terms of the purely radial
electrostatic potential J 1s (r 1 ):
ð d r 2 ½ 1s ðr 2 Þ 1s ðr 2 Þ
r 12
exp ð 2c 0 r 1 Þ
r 1
1
r 1
J 1s ð r 1 Þ¼
¼
ð 1 þ c 0 r 1 Þ 4
:
29 Þ
when use is made of the one-centre Neumann expansion for 1
= r 12
(Magnasco, 2007). Then, integral (4.28) is readily obtained by integration
in spherical coordinates:
ð d r 1 J 1s ð r 1 Þ½ 1s ðr 1 Þ 1s ðr 1 Þ ¼
5
8 c 0
ð 1s 2
j 1s 2
Þ¼
ð 4
:
30 Þ
Optimization of (4.27) with respect to c 0 gives
5
16
c 0 ¼ Z
ð 4
:
31 Þ
as best value for the orbital exponent and
2
5
16
« w ð best Þ¼ Z
:
ð 4
:
32 Þ
as best energy for the S(1s 2 ) configuration of the He-like atom.
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