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therefore becomes:
C AC ¼ L
ð 2
36 Þ
:
Namely, a Hermitian matrix A can be brought to diagonal form by a
unitary transformation with the complete matrix of its eigenvectors.
We examine below the simple case of the 2 2 Hermitian matrix A :
1 S
S 1
A ¼
ð 2
37 Þ
:
The secular equation is
¼ 0
1 l
S
ð 2
38 Þ
:
S
1 l
giving upon expansion the quadratic equation in
l
:
2
l þ 1 S 2
l
2
¼ 0
ð 2
39 Þ
:
with the roots (the eigenvalues):
l
¼ 1 S ;
l
¼ 1 þ S
ð 2
40 Þ
:
1
2
We now turn to the evaluation of the eigenvectors.
(i)
l 1 ¼ 1 S
(
ð 1 l 1 Þ c 1 þ Sc 2 ¼ 0
c 1 þ c 2 ¼ 1
ð 2
41 Þ
:
We solve the homogeneous linear system (2.28) for the first
eigenvalue with the additional constraint of coefficients normal-
ization: 1
1 ¼ l
c 2
c 1
1
S ¼
S
S ¼ 1 ) c 2 ¼ c 1
1
ð 2
42 Þ
:
1 Solution of the homogeneous system is seen to give only the ratio c 2 /c 1 .
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