Chemistry Reference
In-Depth Information
so that
cos
c
2
2
r
H
0
exp
ð
cr
Þ
r cos
½
u
¼
exp
ð
cr
Þð
2c
1
Þ
u
ð
10
:
129
Þ
We then obtain for the integral:
"
#
exp
ð
2cr
Þ
ð
dxx
2
1
1
c
5
p
c
2
2
r
2
h
2p
z
j
H
0
j
2p
z
i¼
drr
2
2
p
ð
2c
1
Þ
r
1
0
2
4
3
5
¼
c
2
2
c
2
2
4
3
2
ð
2c
Þ
4
3
2
ð
2c
Þ
c
2
3
c
5
¼
ð
2c
1
Þ
4
5
ð
10
:
130
Þ
giving for the excitation energy
1
« ¼h
2p
z
j
H
0
E
0
j
2p
z
i¼
2
ð
c
2
c
þ
1
Þ
ð
10
:
131
Þ