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9.6.1 Ethylene (One
p
-Bond, n ¼ 1)
We have n ¼ i ¼ 1, so that the (1 1) secular equation is
H cc ES cc ¼ Q E þ K ¼ 0
j x þ 1 0 ) x ¼ 1 ) E ¼ Q þ K
ð 9
:
68 Þ
which is Pauling's energy of the double bond.
9.6.2 Cyclobutadiene (n ¼ 2)
With reference to the second row of Figure 9.8, we can write for the two
fully equivalent Kekul
e structures 12
c 1 and
c 2
Y ¼ c 1 c 1 þc 2 c 2
ð 9
:
69 Þ
The distinct matrix elements are
<
H 11 ES 11 ¼ H 22 ES 22 ¼ Q E þ 2K K ¼ Q E þ K
1
2 ð Q E þ 4K Þ¼
1
2 ð Q E Þþ 2K
ð 9
:
70 Þ
H 12 ES 12 ¼ H 21 ES 21 ¼
:
giving the (2 2) secular equation
x
2 þ 2
x þ 1
¼ 0
ð 9
:
71 Þ
x
2 þ 2
x þ 1
2
x
2 þ 2
2
) x 2
ð x þ 1 Þ
¼
4 ¼ 0 ) x ¼ 2
ð 9
:
72 Þ
12 Pauling VB theory distinguishes between Kekule structures (all p bonds equal) and Dewar
structures (containing one or more long, i.e. weaker,
p
bonds).
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