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Figure 6-7
Addressing Design Scenario 1 Topology (Answer)
192.168.1.0/26
A
60 Hosts
Address Space
192.168.1.0/25
Fa0/0
RTA
S0/1
DCE
S0/0
192.168.1.120/30
192.168.1.112/30
192.168.1.96/28
192.168.1.64/27
S0/0
DCE
C
S0/1
B
Fa0/0
Fa0/0
S0/1
RTC
RTB
192.168.1.116/30
S0/0
DCE
30 Hosts
10 Hosts
Fill in Table 6-3 with all necessary IP address configuration information for all devices. Use
dotted decimal format for the subnet mask.
2.
Table 6-3
Addressing Table for VLSM Design Scenario 1
Device
Interface
IP Address
Subnet Mask
Default Gateway
RTA
Fa0/0
192.168.1.1
255.255.255.192
S0/1
192.168.1.113
255.255.255.252
S0/0
192.168.1.121
255.255.255.252
RTB
Fa0/0
192.168.1.65
255.255.255.224
S0/1
192.168.1.114
255.255.255.252
S0/0
192.168.1.117
255.255.255.252
RTC
Fa0/0
192.168.1.97
255.255.255.240
S0/1
192.168.1.118
255.255.255.252
S0/0
192.168.1.122
255.255.255.252
HostA
NIC
192.168.1.2
255.255.255.192
192.168.1.1
HostB
NIC
192.168.1.66
255.255.255.224
192.168.1.65
HostC
NIC
192.168.1.98
255.255.255.240
192.168.1.97
List the address space that is still available for future expansion.
3.
For the solution shown in Figure 6-7, the address space still available is .124/30.
Because the given address space is /25, there is no more available space except for the one leftover
WAN subnet.
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