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In-Depth Information
Since the sequence is monotonic increasing, the limit of the sequence is
thelimit of ( a
).
1
10
14
1
1
10
1
999 ·
1
10
1/10
1/10
...
1/10
·
1
.
1
10
1
a
12.45, b
6.78.
With a recurring block of length l , theinfinitedcimal will bethelimit
of a sequence with n th term
1
10
1
1
10
1
10
1
10
b
10
a b
...
a
·
1
10
1
b
1
10
a
1
.
10
1
If a and b are terminating decimals, the sequence with this as n th term
has a rational limit.
15 If A and B are integers and A / B is not equal to a terminating decimal,
thelong division of A by B will not terminate. The remainder at each
stageof thedivision is oneof thenumbrs 1, 2, . . .,
1. Sincethe
process is endless, the remainders must recur and thus the dividends
will recur.
B
16 If thefirst digits to diffr are d
and e
, then we suppose d
e
and so
d
.
Now 0.00 . . . 0 d
1
e
d
... d
(1/10
)(1
1/10
), with equality only
when each d
9, so x
d
. d
d
...( d
1). But also e
. e
e
... e
x
since an infinite decimal sequence is monotonic increasing. Thus
e
. e
e
... e
x
d
. d
d
...( d
1). So
9 for all i .
17 Every rational number is equal to a terminating or recurring decimal.
The infinite decimal given here is neither terminating nor recurring, so
if it converges it does not converge to a rational number.
x e
. e
e
... e
d
. d
d
...( d
1) and e
0, d
18 In theprimefactorisation of both p
, all primes occur to an
even power. So 2 appears to an even power in p and to an odd power
in 2 q ,so p 2 q contradicts the fundamental theorem of arithmetic.
Likewise 3, 6 and 2 cannot berational numbrs.
and q
19 If a
b
2
x were rational, then ( x
a )/ b
2 would also haveto
berational. Contradiction.
 
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