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Figure 2.21 Orthogonal sp 2 b 1 bond hybrid of C 2v symmetry on oxygen overlapping
(shaded area) the h 1 orbital at u ¼ 52 : 5 to give a straight O H bond in H 2 O 28 .
Reprinted from Chemical Physics Letters, 474, Magnasco, V., On the hybridization
problem in H 2 ObyH¨ ckel transformation theory. 212-216, Copyright (2009), with
permission from Elsevier
0
@
1
A
1
2
1
p
p
ð
b 1 b 2
Þ¼ð
by
Þ
ð
2
:
218
Þ
1
2 p
1
2
p
obtaining in this way the three orthonormal sp 2 hybrids of C 2v symmetry:
<
b
þ
y
1
2
b 1
¼
p ¼
p
ð
s sin
z cos
y
Þ
b
y
1
2
ð
2
:
219
Þ
:
b 2
¼
p ¼
p
ð
s sin
z cos v
y
Þ
l
¼
s cos v
z sin v
The hybridization parameter v , arbitrary so far, is best chosen so as the
bondhybrids b 1 and b 2 point in the directionof the twoO
Hbonds, giving
in thisway strongest bondingwithH1s orbitals and satisfying the principle
of maximum overlap. According to Equation (2.214), 2 u ¼
105 gives
40 , and we obtain the set (Figure 2.21):
v
8
<
b 1
¼
0
:
45 34 36 s
þ
0
:
54 25 82 z
þ
0
:
70 71 06 y
¼
hy 1
b 2
¼
0
:
45 34 36 s
þ
0
:
54 25 82 z
0
:
70 71 06 y
¼
hy 2
ð
2
:
220
Þ
:
l
¼
0
:
76 73 27 s
0
:
64 12 55 z
¼
hy 3
28 The equivalent b 2 bond hybrid is obtained by reflection of b 1 across the zx plane.
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