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where
α
=
sin
2
I
X
Y
2
X∆
(0)
S
γ
(0)
=
,
.
Let
|
κ
a
h
|
1. Then
1+
κ
a
h
√
ε
g
ik
0
ε
a
−
√
ε
g
,
ζ
(0)
1
ζ
1
≈
=
ζ
2
≈
,
ik
0
h
√
ε
g
,
−
√
ε
g
,
ζ
(0)
3
ζ
(0)
4
ζ
3
≈
=1
−
4
≈
=
X
+
ζ
(0)
k
0
√
ε
m
,
−
√
ε
m
−
κ
(0)
S
∆
(0)
S
4
ζ
(0)
3
≈
∆
S
≈
=
.
The approximate expression for
κ
S
is obtained under the assumption that
k
(0)
/
(
k
0
ε
m
)
1 , where
k
(0)
is determined by (8.39). This inequality holds
at
T<
10
4
s. Function
k
2
k
(0)
.
k
0
ε
a
|
sin
I
|
i∆
(0)
S
∆
(
k
)=
∆
SK
(
k
)
∆
A
(
k
)
≈−
−
k
(0)
h
near
k
=
k
(0)
For the contribution of the electric mode to the ground field, we get
α
2
k
0
ε
a
k
(0)
h∆
(0)
G
0
=
(1
−
γ
(0)
)
2
sin
I
S
⎛
⎞
√
ε
g
Y
2
ζ
(0
3
∆
(0)
√
ε
g
Y
ζ
(0)
3
−
⎝
⎠
sin
I
S
×
.
(8.55)
γ
(0)
)
γ
(0)
α
Y
(1
−
1
−
∆
(0)
S
−
sin
I
α
If the Hall conductivity is nil (
Y
=4
πΣ
H
/c
= 0), then the wave propagates
in the atmospheric waveguide as a TEM-mode (
E
z
=0
,
z
=0).Inthe
general case (
Y
= 0), we call it a TEM-type wave, keeping in mind, of course,
that the wave has a longitudinal component
b
x
, as well.
The matrix (8.55) is suciently bulky, therefore, let us take into account
that for a wide range of frequencies and conductivities the ground conductiv-
ity is much more than the ionospheric conductivity, i.e.
|
ε
g
|
>X
∼
Y
and
|
k
0
hX
|
1 . Then (8.55) becomes (see (8.39))
⎛
⎞
ik
0
h
Y
2
X
Y
X
−
sin
I
G
0
exp
ik
(0)
x
=
⎝
⎠
exp
ik
(0)
x
.
−
ik
(0)
(8.56)
Y
sin
I
−
ik
0
h
1
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