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where
s m,g = ix ( k 0 ε m,g
k (1) S ) .
Here and below the upper sign refers to ' m ', t he lowe r to ' g '. For s = s m,g
we have k m,g ( s m,g ) = k (1) S . The bra nchof s s m,g ) bei ng determined by
the c ondi tion Re s> 0( Re s m,g > 0). If Re k 0 ε m,g > Re k (1) S , then
Im s m,g > 0, and if Re k 0 ε m,g < Re k (1) S , then Im s m,g < 0 . functions
T m,g
s ±
C 1
s m,g k m,g ( s )
k (1) S
are regular in the vicinity of s =0and s = s m,g
Consider the integral
s exp (
C 1
s m,g
s )
I m,g =
±
k (1) S ds.
k m,g ( s )
0
Use new variable s = t 2
and, with (8.47),
t 2 exp
t 2
2 ix C 1
s m,g
I m,g =
dt.
t 2
s m,g
0
Let us rewrite it in the form
exp
t 2
s m,g
π
2
2 ix C 1
s m,g
2 s m,g
π
1
.
I m,g =
t 2 dt
(8.50)
0
The integral can be expressed in terms of the Kramp function w ( V ) ([1], [8])
which for Im V> 0 is defined by the integral
exp
t 2
w ( V )= 2 iV
π
dt,
(8.51)
V 2
t 2
0
and for Im V< 0 it is found by the analytic continuation of (8.51) into the
lower half-plane. As a result,
exp
t 2
2 V w ( V )+ 0
at
Im V> 0 ,
exp
V 2 /V
dt =
(8.52)
at
Im V< 0 .
V 2
t 2
0
From (8.50) and (8.52) we get
i π
s m,g C 1 1+ i πs m,g w ( s m,g )
x
I m,g =
0
Im s m,g > 0 ,
at
s m,g ) tIm s m,g < 0 .
2 πx C 1 exp (
 
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