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where
s
m,g
=
ix
(
k
0
√
ε
m,g
−
k
(1)
S
)
.
Here and below the upper sign refers to '
m
',
t
he
lowe
r to '
g
'. For
s
=
s
m,g
we have
k
m,g
(
s
m,g
)
=
k
(1)
S
.
The
bra
nchof
√
s
√
s
m,g
) bei
ng determined by
the c
ondi
tion Re
√
s>
0(
Re
√
s
m,g
>
0). If Re
k
0
√
ε
m,g
>
Re
k
(1)
S
,
then
Im
√
s
m,g
>
0, and if Re
k
0
√
ε
m,g
<
Re
k
(1)
S
,
then Im
√
s
m,g
<
0
.
functions
∆
T
m,g
√
s
±
C
−
1
√
s
m,g
k
m,g
(
s
)
k
(1)
S
−
are regular in the vicinity of
s
=0and
s
=
s
m,g
Consider the integral
√
s
exp (
∞
C
−
1
√
s
m,g
−
s
)
I
m,g
=
±
k
(1)
S
ds.
k
m,g
(
s
)
−
0
Use new variable
s
=
t
2
and, with (8.47),
t
2
exp
−
t
2
∞
2
ix
C
−
1
√
s
m,g
I
m,g
=
∓
dt.
t
2
−
s
m,g
0
Let us rewrite it in the form
⎛
⎞
exp
−
t
2
s
m,g
−
√
π
2
∞
2
ix
C
−
1
√
s
m,g
2
s
m,g
√
π
⎝
1
⎠
.
I
m,g
=
∓
−
t
2
dt
(8.50)
0
The integral can be expressed in terms of the Kramp function
w
(
V
) ([1], [8])
which for Im
V>
0 is defined by the integral
exp
t
2
∞
−
w
(
V
)=
2
iV
π
dt,
(8.51)
V
2
−
t
2
0
and for Im
V<
0 it is found by the analytic continuation of (8.51) into the
lower half-plane. As a result,
∞
exp
−
t
2
2
V
w
(
V
)+
0
iπ
at
Im
V>
0
,
iπ
exp
−
V
2
/V
dt
=
−
(8.52)
at
Im
V<
0
.
V
2
−
t
2
0
From (8.50) and (8.52) we get
i
√
π
√
s
m,g
C
−
1
1+
i
√
πs
m,g
w
(
√
s
m,g
)
x
I
m,g
=
∓
0
Im
√
s
m,g
>
0
,
at
∓
s
m,g
) tIm
√
s
m,g
<
0
.
2
πx
C
−
1
exp (
−
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