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the final expression for Φ 4 A :
i A 0 k 0
2
Φ 4 A ≈−
[ C +ln(
Z 0 )] .
(8.25)
Substituting (8.24) and (8.25) into (8.12) and (8.13) for components of the
magnetic mode at the ground, we find
b ( g )
SA
b ( g )
zA
=
i
1
,
A 0
2 π
Y sin I
X
1
x + i ( δ i + h )
A 0
2 π
Y sin I
X
E ( g )
SA ( x )= E ( g )
( x )=
ik 0
[ C +ln(
Z 0 )] .
(8.26)
y
1 the vertical magnetic component b ( g z carries the same infor-
mation about above ionosphere wave structure as the horizontal component
b ( g x . Ratio b ( g z /E ( g y is completely determined by the structure of the field
inside the FLR-region:
For
|
kd g |
ik 0 b ( g )
1
[ x + i ( δ i + h )] [ C +ln(
b x
b z
z
E ( g )
=
Z 0 )] ,
= i.
y
Numerical Examples
Let the ground be a half-space with conductivity σ g , and the ionospheric
model corresponds to the middle latitude dayside ionosphere in the maximum
of solar activity. The half-width δ i and the resonance periods for L =2 , 3 , 4
are found from Fig. 6.6. Chosen parameters are shown in Table 8.1.
Let the total magnetic wave-field above the ionosphere be given by (8.15),
in which instead of b ( i )
0
is substituted by the total amplitude of the incident
Table 8.1. A ground-ionosphere model used in the numerical calculations. σ g is a
specific conductivity of the ground half-space. Σ P and Σ P are the Pedersen and Hall
integral conductivities. The ionospheric model corresponds to the middle latitude
dayside ionosphere in the maximum of solar activity. The half-width δ i of a resonance
shell corresponds to the resonance period for L =2 , 3 , 4. h is the height of the
conductive thin ionospheric layer
Parameter
Value
1 . 6 × 10 8 km/s
Σ P
1 . 75 × 10 8 km/s
Σ H
3 × 10 6 s 1
σ g
h
130 km
δ i
8km ( T =20s, L =2)
δ i
13 . 5km ( T =80s, L =3)
δ i
25 km, ( T = 210 s, L =4)
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