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for which
=cosh kh
tanh kh ,
ζ 1
Y ( e )
1+ ik 0 ε a
kY ( e )
(7.111)
g
g
k 0 ε a sinh kh 1
coth kh ,
ζ 2
Y ( e )
k
ik 0 ε a
kY ( e )
= i
(7.112)
g
g
sinh kh 1+
coth kh ,
ζ 3
Y ( m )
i k 0
k
ik
k 0 Y ( m )
=
(7.113)
g
g
cosh kh 1+
tanh kh .
ζ 4
Y ( m )
ik
k 0 Y ( m )
=
(7.114)
g
g
For the two-layer model
1
Z ( e )
= ik 0 ε g
κ g
1
Z ( m )
= g
k 0
Y ( e )
g
Y ( m )
g
=
cot κ g H,
=
cot κ g H,
(7.115)
g
g
where
κ g = k 0 ε g
k 2 = 2 d 1
g
( kd g ) 2
2
i
.
Admittances Y ( e )
and Y ( m )
i , tend to the electric
and magnetic admittances of the conductive half-space.
Let us find the conditions when the ground can be considered as a perfect
conductive medium. The second term in (7.111)-(7.114) can be neglected for
high enough conductivity if the inequalities
for H
→∞
,cot κ g H
→−
g
g
tan κ g H |
σ a
σ g
κ g
k
coth kh
|
+
|
tanh kh
|
,
κ g tan κ g H |
k
coth kh
|
+
|
tanh kh
|
hold. Then
ζ 1
Y ( e )
ζ 2
Y ( e )
k
k 0 ε a sinh kh,
=
cosh kh,
= i
(7.116)
g
g
ζ 3
Y ( m )
i k 0
k
ζ 4
Y ( m )
=
sinh kh,
=
cosh kh.
(7.117)
g
g
Let us consider first an influence of the conductivity on the electric mode.
The corrective term in (7.111) can be ignored if
tan κ g H tanh kh
ε a
ε g
κ g
k
1 .
(7.118)
The inequality is invalid near the branch cut Im κ g = 0 (Fig.7.3) and imagi-
nary axes of the complex plane of wavenumbers k since tan κ g H and tanh kh
 
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