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φ ) =
6. If ψ : C 2
C 3 is another non-constant rational map of curves over
k
then ( ψ
φ
ψ and ( ψ
φ ) =
ψ
φ .
Proof Most of the claims follow from earlier results such as Lemma 8.2.6 , Theorem 8.2.9
and Lemma 8.2.12 ; also see Proposition II.3.6 of Silverman [ 505 ]. Claim 4 is harder; see
Proposition VII.7.8 and Lemma VII.7.16 of Lorenzini [ 355 ].
Exercise 8.3.9 Give all the details in the proof of Theorem 8.3.8 .
Corollary 8.3.10 Let φ : C 1
C 2 be a non-constant morphism of curves over
k
. Then the
induced maps φ :Pic 0
k
Pic 0
k
( C 1 ) and φ :Pic 0
Pic 0
k
( C 2 )
( C 1 )
( C 2 ) on divisor class
k
groups are well-defined group homomorphisms.
Proof The maps φ and φ are well-defined on divisor classes by parts 2 and 4 of
Theorem 8.3.8 . The homomorphic property follows from the linearity of the definitions.
Exercise 8.3.11 Show that if φ : C 1
k
C 2 is an isomorphism of curves over
then
( C 1 ) =
Pic 0
k
Pic k ( C 2 ) (isomorphic as groups). Give an example to show that the converse is
not true.
A further corollary of this result is that a rational map φ : E 1
E 2
between
elliptic curves such that φ (
O E 1 )
= O E 2 is automatically a group homomorphism (see
Theorem 9.2.1 ).
P
1
→ P
1
=
( x 2 /z 2
=
Exercise 8.3.12 Let φ :
be defined by φ (( x : z ))
:1).Let D
(
1:
1)
+
(0 : 1). Compute φ ( D ), φ ( D ), φ φ ( D ) and φ φ ( D ).
We now make an observation that was mentioned when we defined φ on
(1 : 0)
k
( C 1 ).
Lemma 8.3.13 Let φ : C 1
C 2 be a non-constant morphism of cur v es over
k
. Let f
( C 1 ) and Q
k
C 2 (
k
) . Suppose that v P ( f )
=
0 for all points P
C 1 (
k
) such that φ ( P )
=
Q. Then
f ( P ) e φ ( P )
f ( φ ( Q )) .
N k ( C 1 ) ( k ( C 2 )) ( f )( Q )
=
=
P C 1 (
k
= Q
): φ ( P )
Another formulation would be: f of conorm of Q equals norm of f at Q.
Proo f (Sketch) This uses similar ideas to the proof of part 4 of Theorem 8.3.8 .Wework
over
.
As always,
k
( C 1 ) is a finite extension of φ (
φ (
k
k
( C 2 )). Let A
=
O Q ( C 2 )) and let B be
( C 1 ). Then B is a Dedekind domain and the ideal φ (m Q )
the integral closure of A in
k
splits as a product i m e φ ( P i )
where P i
C 1 (
k
) are distinct points such that φ ( P i )
=
Q .
P i
By assumption, f has no poles at P i and so f
B . Note that f ( P i )
=
c i ∈ k
if and only
if f
c i (mod m P i ). Hence, the right-hand side is
c e φ ( P i )
i
f ( P i ) e φ ( P i )
( f (mod m P i )) e φ ( P i ) .
=
=
i
i
i
 
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