Biomedical Engineering Reference
In-Depth Information
transpose notation in ( 3.30 ) is not necessary. In the next paragraph the conservation
of angular momentum is used to show that the stress tensor T is symmetric.
The arguments to show that the stress tensor T is symmetric are algebraically
simpler if we replace the statement of the conservation of angular momentum given
above, ( 3.26 ), by the equivalent requirement that the skew-symmetric part of Z ,
ð
ð
ð
Z
¼
x
x
r
d v
x
t d a
x
r
d d v
;
(3.31)
O
@
O
O
be zero:
Z T
Z
¼
0
:
(3.32)
Equation ( 3.32 ) is equivalent to ( 3.26 ). The rationale for this equivalence is
that the components of the cross-product of two vectors, say a
b , are equal to
the components of the skew-symmetric part of the open product of the two vectors,
a b . Since ( 3.32 ) requires that Z be symmetric, it follows that the skew-
symmetric part of Z is zero. Equation ( 3.26 ) is equivalent to the skew-symmetric
part of Z , and the equivalence is established.
The sequence of steps applied to the conservation of linear momentum in the
paragraph before last are now applied to the expression ( 3.31 ) for Z . The point form
of ( 3.31 ) is obtained by first substituting ( 3.16 ) into the surface integral in ( 3.31 ),
ð
ð
ð
Z
¼
x
x
r
d v
x
Tn d a
x
r
d d v
;
(3.33)
O
@O
O
then applying the divergence theorem (A184) to the surface integral in ( 3.33 ),
ð
ð
O fðr
ð
Z
¼
x
x
r
d v
x
Þ
T
þð
x
r
T
Þg
d v
x
r
d d v
:
(3.34)
O
O
This result is simplified by observing that
x
¼
1 and collecting all the
remaining integrals containing x
together, thus
ð
ð
T T
fr
Z
¼
T d v
þ
x
x
r
r
d
Þ
d v
:
(3.35)
O
O
The second integral in ( 3.35 ) is exactly zero because its integrand contains the
point form statement of linear momentum conservation ( 3.30 ); thus ( 3.35 ) and
( 3.32 ) show that
ð
O ð
T T
T
Þ
d v
¼
0
:
(3.36)
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