Biomedical Engineering Reference
In-Depth Information
transpose notation in (
3.30
) is not necessary. In the next paragraph the conservation
of angular momentum is used to show that the stress tensor
T
is symmetric.
The arguments to show that the stress tensor
T
is symmetric are algebraically
simpler if we replace the statement of the conservation of angular momentum given
above, (
3.26
), by the equivalent requirement that the skew-symmetric part of
Z
,
ð
ð
ð
Z
¼
x
x
r
d
v
x
t
d
a
x
r
d
d
v
;
(3.31)
O
@
O
O
be zero:
Z
T
Z
¼
0
:
(3.32)
Equation (
3.32
) is equivalent to (
3.26
). The rationale for this equivalence is
that the components of the cross-product of two vectors, say
a
b
, are equal to
the components of the skew-symmetric part of the open product of the two vectors,
a b
. Since (
3.32
) requires that
Z
be symmetric, it follows that the skew-
symmetric part of
Z
is zero. Equation (
3.26
) is equivalent to the skew-symmetric
part of
Z
, and the equivalence is established.
The sequence of steps applied to the conservation of linear momentum in the
paragraph before last are now applied to the expression (
3.31
) for
Z
. The point form
of (
3.31
) is obtained by first substituting (
3.16
) into the surface integral in (
3.31
),
ð
ð
ð
Z
¼
x
€
x
r
d
v
x
Tn
d
a
x
r
d
d
v
;
(3.33)
O
@O
O
then applying the divergence theorem (A184) to the surface integral in (
3.33
),
ð
ð
O
fðr
ð
Z
¼
x
€
x
r
d
v
x
Þ
T
þð
x
r
T
Þg
d
v
x
r
d
d
v
:
(3.34)
O
O
This result is simplified by observing that
∇
x
¼
1
and collecting all the
remaining integrals containing
x
together, thus
ð
ð
T
T
fr
€
Z
¼
T
d
v
þ
x
x
r
r
d
Þ
d
v
:
(3.35)
O
O
The second integral in (
3.35
) is exactly zero because its integrand contains the
point form statement of linear momentum conservation (
3.30
); thus (
3.35
) and
(
3.32
) show that
ð
O
ð
T
T
T
Þ
d
v
¼
0
:
(3.36)
Search WWH ::
Custom Search