Biomedical Engineering Reference
In-Depth Information
The components of the vector
U
S
d
¼ S
d
U
are given by
1
K
1
;
1
K
2
;
1
K
3
;
1
K
4
;
1
K
5
;
1
K
6
U
S
d
¼
;
(8.33a)
where
1
K
m
S
m
S
m
S
m
a
¼
þ
þ
ða ¼
1
; ...;
6
Þ
(8.33b)
a
a
a
1
2
3
in the case of no (triclinic) symmetry, and by
12
13
1
K
1
;
1
K
2
;
1
K
3
;
1
K
1
¼
1
n
n
S
m
U
¼
0
;
0
;
0
;
;
E
1
m
m
23
m
m
32
1
K
2
¼
1
n
21
n
1
K
3
¼
1
n
13
n
;
;
E
2
E
3
m
31
1
K
1
;
1
K
1
;
1
K
3
;
1
K
3
¼
1
2
n
1
K
1
¼
1
K
2
S
m
U
¼
0
;
0
;
0
;
;
E
3
12
n
13
21
n
23
1
n
1
n
¼
¼
;
E
1
E
2
n
m
1
K
m
½
1
K
m
¼
1
2
3
K
1
¼
1
K
m
S
m
S
m
U
U
U
¼
1
;
1
;
1
;
0
;
0
;
0
;
;
¼
E
m
3
ð
1
2
n
m
Þ
¼
(8.34)
E
m
in the cases of orthotropic, transversely isotropic, and isotropic symmetries, respec-
tively. As may be seen from (8.33) the incompressibility condition
U S
d
¼ S
d
U ¼
0
requires that
S
d
be singular, Det
S
d
¼
0. From (
8.32
)and(
8.34
) the incompressibility
S
d
¼ S
d
U
U
condition
0 is expressed in terms of Poisson's ratios for the
orthotropic, transversely isotropic and isotropic symmetries by
¼
E
1
E
3
E
1
E
3
E
1
E
1
þ
m
m
m
n
12
¼
E
3
Þ
; n
13
¼
1
E
3
Þ
; n
23
¼
E
3
;
(8.35)
E
2
ð
E
1
þ
E
2
ð
E
1
þ
E
1
E
1
1
2
m
m
m
n
12
¼
1
2
E
3
;
n
13
¼
2
E
3
;
n
31
¼
(8.36)
and
2, respectively.
The significance of these incompressibility results is illustrated here by simple
geometric considerations. Consider an incompressible isotropic material for which
one must have
n
m
¼
1
=
a
3
is
extended by a uniform tensile stress in one direction, the length in that extension
direction becomes
a
m
n
¼
1
=
2 . If a cube of this material with a volume
V
o
¼
þ D
EX
a
and the lengths of the other two faces become
a
þ D
a
.
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