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The formal solution to the linear equation of motion ( 3.10 ) is given by
q
(
t
) =
A 0 cos
[ ω 0 t
+ φ 0 ] ,
(3.12)
with the amplitude A 0 and phase
φ 0 determined by the oscillator's initial conditions
p 2
(
0
)
q 2
A
=
(
0
) +
0 ,
(3.13)
2
ω
p
(
0
)
φ 0 =−
) .
tan
(3.14)
ω 0 q
(
0
Figure 3.1 (a) depicts the harmonic-oscillator potential with two distinct energy levels
shown as flat horizontal line segments. Figure 3.1 (b)isthe
(
,
)
phase space for the
oscillator and the two curves are energy-level sets, namely curves of constant energy for
the two energy levels in Figure 3.1 (a). The energy-level sets are ellipses for
p
q
ω 0 >
1 and
circles for
ω 0 =
1
.
(a)
1
0.8
0.6
0.4
0.2
-75
-50
-25
Displacement q
0
25
50
75
100
(b)
1
0.75
0.5
0.25
0
-0.25
-0.5
-0.75
-0.75
-0.5
-0.25
0
0.25
0.5
0.75
1
Displacement q
Figure 3.1.
(a) The harmonic potential function V ( q ) is plotted versus q and two energy levels are denoted.
(b) The orbits for the energy level depicted in (a) are shown in the ( q , p ) phase space.
 
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