Game Development Reference
In-Depth Information
Here is how your work proceeds:
3
2
z ¼
4
y
B
Start with B from STEP 3
:
z ¼
2
C
Start with C from STEP 3
:
z ¼
3
2
3
2
ð
2
Þ
3
2
:
C
Multiply C by
:
3
2
z ¼
3
3
2
C
Simplify C
to B;
y
known
3
2
y ¼
1
B
Add C
:
This then provides you with the value of
y
. At the same time, it remains for you to
eliminate the
z
variable from equation A. To eliminate the
z
variable from
equation A, you repeat much of the activity you just performed. This time around,
you consider that the coefficient of
z
in equation A is 3. Given this value, you
multiply equation C by
3 to arrive at an equation you can subtract from equation
Atoremovethe
z
variable from equation A. Here is how your work proceeds:
x
2
y þ
3
z ¼
11
A
Start with A from STEP 3
:
ð
3
Þz ¼
3
ð
2
Þ
C
Multiply C by
3
:
3
z ¼
6
C
Simplify C
:
x
2
y ¼
5
A
Add C to A
:
STEP 4
Now that you have eliminated the
z
variable from equation A, your system of
equations takes the following form:
x
2
y ¼
5
A
x
not yet isolated
:
y ¼
1B
y
is known
:
:
You have yet to isolate
x
. When you accomplish that task, you then have all the
values for the three variables. From your work so far on equation B, you know
that
y ¼
1, so you can use this knowledge to eliminate the
y
variable from
equation A in a ready fashion. Accordingly, the coefficient of
y
in equation A is
z ¼
2
C
z
is known
