Game Development Reference
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the inverse of the coefficient. In this case, the inverse of 2 is 2 , so your work takes
the following form:
2 x 2
2
3 x
2
1
2 ¼ 0
Multiply by 1
2 :
3
2 x ¼
1
2
x 2
! 2
¼
! 2
3
2
2
3
2
2
3
2 x þ
1
2 þ
x 2
3
2 x þ
9
16 ¼
1
2 þ
9
16
x 2
3
2 x þ
9
16 ¼
8
16 þ
9
16
x 2
3
2 x þ
9
16 ¼
17
16
x 2
2
3
4
17
16
x
¼
r
17
16
3
4 ¼
x
Having proceeded this far, you can then rationalize the denominator of the
expression on the left side of the equation. This gives you
p
17
3
4 ¼
x
4
The solution set for the equation is as follows:
p
17
p
17
3 þ
, 3
4
4
Exercise Set 9.1
Solve by completing the square.
a. p 2
þ 5p 3 ¼ 0
b. q 2
10q 22 ¼ 0
 
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