Game Development Reference
In-Depth Information
the inverse of the coefficient. In this case, the inverse of 2 is
2
, so your work takes
the following form:
2
x
2
2
3
x
2
1
2
¼
0
Multiply by
1
2
:
3
2
x ¼
1
2
x
2
!
2
¼
!
2
3
2
2
3
2
2
3
2
x þ
1
2
þ
x
2
3
2
x þ
9
16
¼
1
2
þ
9
16
x
2
3
2
x þ
9
16
¼
8
16
þ
9
16
x
2
3
2
x þ
9
16
¼
17
16
x
2
2
3
4
17
16
x
¼
r
17
16
3
4
¼
x
Having proceeded this far, you can then rationalize the denominator of the
expression on the left side of the equation. This gives you
p
17
3
4
¼
x
4
The solution set for the equation is as follows:
p
17
p
17
3
þ
,
3
4
4
Exercise Set 9.1
Solve by completing the square.
a. p
2
þ 5p 3 ¼ 0
b. q
2
10q 22 ¼ 0