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(
) =
() +
( ,
Ma
uv
+
b
aM
u
bM
v
for all vectors u and v and real numbers a and b.
Proof.
We shall show that M is a linear transformation in two steps.
Claim 1.
M( u + v ) = M( u ) + M( v ).
Define a vector w by the equation
uv w
+=2.
(2.15)
This equation can be rewritten as
1
2
(
)
wu
=+
vu
-
.
(2.16)
See Figure 2.6. Since M( 0 ) = 0 (which implies that |M( p )| = | p | for any vector p ), we
can use equation (2.15) and Lemma 2.2.2 to conclude that
(
) =
()
M
uv
+
2
M
w
.
(2.17)
Similarly, equation (2.16) and Lemma 2.2.2 implies that
1
2
() =
() +
(
() -
()
)
MM
wu
MM
v
u
.
(2.18)
Substituting the expression for M( w ) in equation (2.18) into equation (2.17) and sim-
plifying the result proves Claim 1.
Claim 2.
M(c v ) = cM( v ), for any real number c.
This follows from Lemma 2.2.2 (let A = 0 , B = v , and t = c in that Lemma). Theorem
2.2.4.1 is proved.
u + v
M(u + v) = 2M(w)
M(v)
u
w
M (w)
v
M(u)
Figure 2.6.
Proving motions are linear
transformations.
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