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This definition has the advantage that one does not need to know a normal vector for
the line (only a direction vector or a second point B on the line). Of course, finding a
normal vector to a line in the plane is trivial. On the other hand, our normal vector
definition of a reflection will generalize to higher dimensions later.
Finally, since
=+ (
)
Q
P
PA • N N
,
we see that Q is the point where the line through P that is orthogonal to L meets L .
Therefore, another definition of S( P ) is that we solve for that point Q and then define
() =+2.
S PPPQ
(2.11)
To put it another way, the segment PP ¢
is perpendicular to the line L and intersects
the line at its midpoint Q .
2.2.3.1. Theorem.
Let S be the reflection about a line L .
(1) The definition of S depends only on L and not on the point A and the normal
vector N that are chosen in the definition. The three definitions of a reflection
specified by equations (2.9), (2.10), and (2.11) are equivalent.
(2) If t is chosen so that P + t N is the point where the line through P with direc-
tion vector N meets the line L , then S( P ) = P + 2t N .
(3) The fixed points of S are just the points on its axis L .
(4) If L is the axis of a reflection S and L ¢
is a line orthogonal to L , then
S( L ¢) = L ¢.
(5) Reflections are motions.
Proof.
Exercise.
2.2.3.2. Example.
To find the reflection S x about the x-axis.
Solution.
If we choose A = (0,0) and N = (0,1), then PA =- P and
() =+ ()()
[
] ()
S x PP
2
P
•,
0 1
0 1
,,
or
(
) =-
(
)
Sxy
,
x y
,
.
x
In other words, S x has equations
xx
y .
¢=
¢=-
(2.12)
2.2.3.3. Example.
To find the reflection S about the line L defined by the equation
2x - y + 2 = 0.
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