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{
}
GH
=
gH g G
Œ
and
(
) (
) =◊
(
)
gH
g H
g g H
,
1
2
1
2
for all g 1 , g 2 ΠG.
It is straightforward to check that the normality of H implies that (G/H,·¢) is a
well-defined group usually denoted simply by G/H. If H is the trivial subgroup, then
one always identifies G/H with G in the natural way.
B.4.16. Example.
If G = Z 9 and H = {0,3,6}, then G/H ª Z 3 .
If G = Z 2 and H = Z , then G/H ª Z .
B.4.17. Example.
B.4.18. Example.
If G = Z and H = {kn | k Œ Z }, then G/H ª Z n.
B.4.19. Lemma.
Let G and H be groups. If f : G Æ H is a surjective homomorphism,
then
(
)
HG
ª
ker
f
.
Proof.
Let K = ker f. Simply check that the map
GK
Æ
Æ ()
H
gK
f g
is an isomorphism.
A group G is said to be cyclic if G = {1, g, g 2 , . . .} for some fixed element
Definition.
g in G.
It is easy to see that a cyclic group G is abelian and that the group G in the defi-
nition is just Z g using additive notation. The standard examples of cyclic groups are
ZZ
=
1
and
ZZ
=
k for k in
,
Z
and k relatively prime to n
.
n
n
It follows from the next lemma that there are no others.
B.4.20. Lemma.
A cyclic group G is isomorphic to either Z or Z n for some positive
integer n.
Proof.
Let G = Z g and define a homomorphism
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