Graphics Reference
In-Depth Information
The cylindrical frame field on R 3 .
Figure 9.36.
U 3
U 2
U 1
with respect to some open subset (submanifold) of R 3 . In fact, any set for which one
can make sense of the differentiability of functions would be adequate.
9.16.8. Example. To compute the connection forms for the cylindrical frame field
( U 1 , U 2 , U 3 ) on R 3 defined by
() = (
)
( ) + (
)
( )
Up
cos
q
Ep
sin
q
E p
1
1
2
() =-
(
)
( ) + (
)
( )
Up
sin
q
Ep
cos
q
Ep
2
1
2
() =
()
Up Ep
,
3
3
where points are expressed in cylindrical coordinates (r,q,z). See Figure 9.36.
Solution. Note that this field is not defined along the z-axis, but as long as we stay
away from that axis everything that we did applies. Let v be a tangent vector at the
point p . By definition
() =
(
(
)
)
( ) +
(
(
)
)
( )
Up
D
cos
q
Ep
D
sin
q
E p
v
1
v
1
v
2
() =-
(
(
)
)
( ) +
(
(
)
)
( )
Up
D
sin
q
Ep
D
cos
q
Ep
v
2
v
1
v
2
() =
Up 0
.
v
3
All that is left to do is to substitute into the formulas
( () =—
()
( .
w ij
pv
Up Up
v
i
j
For example,
( () =
(
(
(
)
)
( ) +
(
(
)
)
( )
) ∑-
(
(
)
( ) + (
)
( )
)
w
pv
D
cos
q
Ep
D
sin
q
Ep
sin
q
Ep
cos
q
Ep
12
v
1
v
2
1
2
(
)
(
) + (
)
(
)
=-
sin
q
D
cos
q
cos
q
D
sin
q
.
v
v
Using the relationships
(
) =-
(
)
( )
D
cos
q
sin
q
d
q
v
v
(
) = (
)
( )
D
sin
q
cos
q
d
q
v
v
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