Graphics Reference
In-Depth Information
cross product is a “product” that behaves very much like the product in the case of
real numbers except that it is not commutative. The two operations of vector addi-
tion and the cross product make R 3 into a (noncommutative) ring . Is there a similar
product in other dimensions? Unfortunately not, but the cross product does arise from
a general construction that applies to all dimensions and that is worth looking at
because it will give us additional insight into the cross product.
Let v 1 , v 2 ,..., v n-1 ΠR n . Define a map T : R n
1.10.1. Theorem.
Æ R by
v
Ê
ˆ
1
Á
Á
Á
˜
˜
˜
M
() =
T
w
det
.
v
n
-
1
Ë
¯
w
Then there is a unique u ΠR n such that T( w ) = u w for all w .
Proof. This theorem is an immediate corollary to Theorem 1.8.2 because properties
of the determinant function show that T is a linear functional.
Definition. Using the notation of Theorem 1.10.1, the vector u is called the ( gener-
alized ) cross product of the vectors v 1 , v 2 ,... v n-1 and is denoted by v 1 ¥ v 2 ¥ ···¥
v n-1 .
1.10.2. Proposition.
The generalized cross product satisfies the following basic
properties:
(1) It is commutative up to sign, that is,
() ¥
v
¥
v
¥◊◊◊¥
v
=
sign
s
v
v
¥◊◊◊¥
v
()
()
(
)
s
1
s
2
s
n
-
1
1
2
n
-
1
for all permutations s of {1, 2,..., n - 1}.
(2) It is a multi-linear map, that is,
v
¥◊◊◊¥
a
v
¥◊◊◊¥
v
=
a
(
v
¥◊◊◊¥
v
¥◊◊◊¥
v
)
1
i
n
-
1
1
i
n
-
1
(
) ¥◊◊◊¥
¢
(
) +
(
)
v
¥◊◊◊¥
v
+
v
v
=
v
¥◊◊◊¥
v
¥◊◊◊¥
v
v
¥◊◊◊¥
v
¢ ¥◊◊◊¥
v
1
i
i
n
-
1
1
i
n
-
1
1
i
n
-
1
(3) ( v 1 ¥ v 2 ¥ ···¥ v n-1 )• v i = 0 , for all i.
(4) If the vectors v i are linearly independent, then the ordered basis
(
)
vv
,
,
◊◊◊
v
,
v v
¥
¥◊◊◊¥
v
12
n
-
11
2
n
-
1
induces the standard orientation on R n .
Proof. Facts (1) and (2) are immediate from the definition using properties of the
determinant. Fact (3) follows from the observation that the determinant of a matrix
with two equal rows is zero, so that each v i lies in the kernel of T in Theorem 1.10.1.
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