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(
)( ) =-
(
)
f
o
F
q
cos
q
,
-
sin
q
and this map is clearly C . If p 0 = (x 0 ,y 0 ) with y 0 > 0, then we could have chosen another
local C parameterization such as
(
) Æ
S
Y:
-
11
,
,
where
(
)
() =
2
Y xx
,
1
-
x
.
This time
(
)
(
)( ) =- -
2
f
o
Y
x
x
,
1
-
x
,
which is also C .
Definition. Let f : M n Æ N k be a differentiable map between differentiable mani-
folds. If f has rank n at all points of M , the f is said to be an immersion . If f is a
homeomorphism onto f( M ) Õ N and is an immersion, then f is called an imbedding .
If f is a homeomorphism between M and N and an immersion, then it is called a
diffeomorphism .
Immersions may only be locally one-to-one. For example, a figure eight is an
immersion of a circle in the plane but not an imbedding.
8.3.10. Theorem. If f : M n
Æ N k
is a diffeomorphism, then n = k and f -1 : N Æ M is
also a diffeomorphism.
Proof. The fact that n = k follows from the invariance of domain theorem, Theorem
7.2.3.8. Since f is a homeomorphism, it has an inverse which is also a homeomor-
phism. To prove that f -1
is a diffeomorphism, use the inverse function theorem,
Theorem 4.4.2.
Definition. A differentiable manifold N k that is a subset of a closed manifold M n is
called a (differentiable) submanifold of M n if the inclusion map is an immersion. If
the manifold M n has a nonempty boundary, then we also require that for every p Œ
N k , there is an open neighborhood U of p in M n , an imbedding h : U Æ R n , and an
open subset V Ã R k + Ã R n , so that N k
« U = h -1 ( V ).
The reason for the complication in the case of manifolds with boundary is that
we do not want N to meet the ∂ M in a bad way. See Figure 8.11(a) for some cases of
h, U , and V . Figure 8.11(b) shows some good submanifolds and Figure 8.11(c) some
imbedded manifolds that we would not want to call submanifolds. Among other
things, unless N is contained in ∂ M , N -∂ N should not meet ∂ M and ∂ N should always
meet ∂ M nicely (“nice” means transversally as defined in Section 8.11).
Finally, another common term is the following:
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