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Suppose that h : R n
Æ R m is a homeomorphism. Define
n
m
H
: SS
Æ
by
() = (
) ()
-
1
H
x
p
oo
h p
x
,
if
x
π
e
,
and
mn
n
+
1
(
) =
H
e
e
.
n
+
1
m
+
1
The map H will be a homeomorphism and therefore n = m by part (1). The theorem
is proved.
The next three theorems are less trivial.
7.2.3.6. Theorem. (Invariance of Dimension) If K and L are simplicial complexes
with ΩKΩªΩLΩ, then dim K = dim L.
Proof.
See [AgoM76].
Definition. The dimension of a polyhedron is defined to be the dimension of any
simplicial complex that triangulates it.
Theorem 7.2.3.6 shows the dimension of a polyhedron is a well-defined topologi-
cal invariant.
7.2.3.7. Theorem. (Invariance of Boundary) If K and L are simplicial complexes
and h : ΩKΩÆΩLΩ is a homeomorphism, then h(Ω∂ KΩ) =Ω∂LΩ.
Proof.
See [AgoM76].
Theorem 7.2.3.7 makes it possible to define the boundary of a polyhedron.
Definition.
Let X be a polyhedron. Define the boundary of X , denoted by ∂ X , by
(
K,
X =
j∂
where (K,j) is any triangulation of X .
7.2.3.8. Theorem (Invariance of Domain) If U and V are homeomorphic subsets of
R n and if U is open in R n , then so is V .
Proof.
See [AgoM76].
Returning to our definition of topological manifolds in Section 5.3, we are finally
able to prove the claimed invariance of two aspects of the definition.
7.2.3.9. Corollary.
The dimension of a topological manifold and its boundary are
well defined.
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