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for x . We shall work out the case where n is 2 as an example.
4.7.1. Example.
To find a root to the system of equations
(
) =
fxy
gxy
,
,
0
0
(
) =
.
Solution. We define a sequence of points (x k ,y k ) that converge to the root. Suppose
that we already have defined the kth point (x k ,y k ). The Taylor expansions for f and g
around (x k ,y k ) are
(
) = (
) +
(
)
(
) +
(
)
(
) +
fxy fxy
,
,
fxy xx
,
-
fxy yy
,
-
...
k k
xk k
k
yk k
k
(
) =
(
) +
(
)
(
) +
(
)
(
) +
gxy gxy
,
,
gxy xx
,
-
gxy yy
,
-
...
k k
xk k
k
yk k
k
Truncating higher order terms means that we want to solve
(
)
(
) +
(
)
(
) =- (
)
fx y x x
,
-
fx y y y
,
-
fx y
,
xk k
k
yk k
k
k k
(
)
(
) +
(
)
(
) =- (
)
gxy x x
,
-
gxy y y
,
-
gxy
,
.
xk k
k
yk k
k
k k
Cramer's rule implies that
=+ -+
fg
gf
y
y
x
x
k
+
1
k
J
=+ -+
gf
fg
x
x
y
y
,
k
+
1
k
J
where J = f x g y - g x f y and all the partials are evaluated at (x k ,y k ). If (x 0 ,y 0 ) is an approx-
imation to a root (a,b), then one can show that convergence to (a,b), if any, is quad-
ratic. Conditions that are sufficient to guarantee such convergence assuming that
(x 0 ,y 0 ) is “close enough” to (a,b) are of the type:
(1) The derivatives of f and g up to order 2 are continuous and bounded in a
neighborhood U of (a,b).
(2) The Jacobian J does not vanish in U .
See [ConD72].
Now methods for finding zeros of functions have a much wider application than
simply that specific problem. Many other problems can be rephrased in those terms.
Specifically, problems that involve finding the inverse of a function are often rephrased
in terms of finding solutions to an equation of the form (4.14). As an example of that
type of problem, suppose that one is given a function p : R 2 Æ R 3 , a point q Œ R 3 , and
one wants to find values x and y so that p(x,y) = q . This problem can be expressed in
terms of finding a zero of the function
(
) =- (
)
fxy
,
q
pxy
,
.
(4.16)
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