Image Processing Reference
In-Depth Information
where
x
is a known random variable of which the PDF
px
x
()
is known. Then to
find
py
y
()
, it suffices to solve the equation
y
=
g
(
x
). Indeed, if the real roots of
Equation 4.167 are denoted by
x
, , , ,
……
x
r
such that
1
ygx
=
()
=
=
g
r
()
=
,
(4.168)
1
Then
py
y
()
is given by
px
gx
()
()
px
gx
()
()
x
1
1
x
n
py
()
=
|
′
|
++
|
′
|
+
,
(4.169)
y
r
where
g
′
(
x
) is the derivative of
g
(
x
).
4.7.1.2
Example
Let
yx
=
As an example, suppose the PDF
px
x
()
of
x
is known. Then, the PDF of
y
,
given by
yx
=
,
(4.170)
is
py
()
=
2
ypy
( ),
2
(4.171)
y
x
for
y
≥
0.
4.7.2
G
ENERAL
T
HEOREM
Given a random vector
x
=
(
x
n
,...,
) ,
T
(4.172)
1
whose components
x
are random variables and given
k
functions
i
g
1
()
x
,...,
g
k
( ,
x
(4.173)
we form a
new set of random variables:
y
=
g
()
x
,...,
y
=
g
( .
x
(4.174)
1
k
k
1
Assume
k
=
n
. To find the PDF
p
y
(
y
1
,
…
,
y
n
) of the random vector
y
=
(
y
1
,
…
,
y
n
)
T
for a specific set of numbers
y
1
,
…
,
y
n
, we solve the system
g
()
x
= ,...,
y
g
()
x
=
y
,
(4.175)
1
1
n
n
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