Image Processing Reference
In-Depth Information
where
x
is a known random variable of which the PDF
px
x ()
is known. Then to
find
py
y ()
, it suffices to solve the equation y
=
g ( x ). Indeed, if the real roots of
Equation 4.167 are denoted by
x
, , , ,
……
x r
such that
1
ygx
=
()
=
=
g r
()
=
,
(4.168)
1
Then
py
y ()
is given by
px
gx
()
()
px
gx
()
()
x
1
1
x
n
py
()
= |
| ++ |
| +
,
(4.169)
y
r
where g
( x ) is the derivative of g ( x ).
4.7.1.2
Example
Let
yx
=
As an example, suppose the PDF
px
x ()
of
x
is known. Then, the PDF of
y
,
given by
yx
=
,
(4.170)
is
py
()
=
2
ypy
( ),
2
(4.171)
y
x
for y
0.
4.7.2
G ENERAL T HEOREM
Given a random vector
x
=
(
x n
,...,
) ,
T
(4.172)
1
whose components
x
are random variables and given k functions
i
g
1 ()
x
,...,
g k
( ,
x
(4.173)
we form a new set of random variables:
y
=
g
()
x
,...,
y
=
g
( .
x
(4.174)
1
k
k
1
Assume k
=
n . To find the PDF p y ( y 1 ,
, y n ) of the random vector
y
=
( y 1 ,
, y n ) T
for a specific set of numbers y 1 ,
, y n , we solve the system
g
()
x
= ,...,
y
g
()
x
=
y
,
(4.175)
1
1
n
n
 
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