Digital Signal Processing Reference
In-Depth Information
(A.3), the second-order distortion can also be expressed in terms of more prac-
tical design parameters such as the closed-loop transconductance G m , the bias
current I ds and the overdrive voltage V gst (A.33):
i ds ,peak
I ds
(V gs V T )
2 I ds
1
8
hd 2,cl
=
G m
(A.33)
The closed-loop transconductance G m represents the useful gain that is eventu-
ally available from this system. Furthermore, the bias current I ds will define the
power consumption of the amplifier setup. Note that if the power consumption
is a fixed constraint, the linearity can still be improved by decreasing the over-
drive voltage, completely opposite to the intuitive solution suggested earlier.
The reason for this behaviour is that a constant drain-source current leads to
a quadratical increase of the dimensions of the transistor (W/L) , thereby also
increasing the small-signal gain g m . A major pitfall of improving the linearity
in this way is that the high-frequency performance of the system will collapse
under the increased load of parasitic capacitances.
The simplified mos transistor model used in these calculations does not con-
tain any third-order coefficients. When the transistor is used in an open-loop
topology, no third-order distortion components will thus appear at the output.
However, from Equation (A.24) it is clear that third-order components appear
in the degenerated amplifier setup after all. By following the same strategy
as for the second-order distortion, and employing the polynomial coefficients
from (A.29) in hd 3,cl , the following expressions are obtained for the third-
order harmonic distortion (A.34):
v 2
1
32
g m R S
g,peak
(V gs
=
hd 3,cl
V T ) 2
( 1
+
g m R S ) 4
i ds ,peak
I ds
2
G m
g m
2
1
32
=
g m R S
(A.34)
While these formulas might look very impressive or confusing for the reader, it
is far more interesting to look back to the closed-loop second-order harmonic
distortion formula of A.32. It seems that the third-order distortion of A.34 is
related to HD 2,CL in the following manner (A.35):
1
8
G m
g m
2
i ds ,peak
I ds
hd 3,cl
=
2
g m R S
2 hd 2,cl 2
=
g m R S
=
g m hd 2,cl
R S 2hd 2,cl
=
g m h d 2,c l
R S
im 2, c l
( 3 )
(A.35)
( 2 )
( 1 )
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