Civil Engineering Reference
In-Depth Information
E
s
E
c
200 000
29 961
6
:
68
α
s
E
L
E
c
170 000
29 961
5
:
67
α
L
q
5
:
67
?
0
:
00088
6
:
67
?
0
:
0028
2
x
5
:
67
?
0
:
00088
6
:
67
?
0
:
0028
160
160
6
:
67
?
0
:
0028
?
140
160
2
?
5
:
67
?
0
:
00088
?
?
160
29
:
36 mm
Using these figures it is now possible to determine the strain in the reinforcing steel:
α
N
1
=
2
α
N
1
x
a
d
L
x
a
d
a
=
2
a
s
Lr
l
b
ε
sRk
l
b
κ
VB
?
κ
bsk
?
?
0
:
25
1
=
2
140
29
:
36
160
29
:
36
a
sRk
l
b
1
:
0
?
0
:
0036
?
0
:
25
1
=
2
ε
0
:
155
1
:
35 mm
=
m
?
To calculate the admissible moment, the internal lever arms are still required, which can
be determined in simplified form via the compression zone:
z
L
h
k
a
?
x
h
0
:
4
?
x
160
0
:
4
?
29
:
36
148
:
26 mm
z
s
d
k
a
?
x
h
0
:
4
?
x
140
0
:
4
?
29
:
36
128
:
26 mm
Therefore, the admissible moment at the
flexural crack nearest the support is
1
γ
BA
ε
1
γ
S
a
LRk
l
b
?
E
Lm
?
A
L
?
z
L
?
a
sRk
l
b
?
E
s
?
A
s
?
z
s
?
m
Rd
l
b
ε
1
1
:
5
1
1
:
15
43
?
10
2
?
10
3
m
Rd
l
b
1
:
40
?
170
?
140
?
148
:
26
?
1
:
35
?
200
?
4
:
?
128
:
26
?
3
:
29
13
:
32
16
:
61 kNm
=
m
The acting moment results from the position of the
flexural crack closest to the support
and the 'shift rule', which in this analysis according to DAfStb guideline part 1 section
9.3.1.1 (RV 10) may be assumed to be
h
/2 for solid slabs:
2
h
2
p
?
x
cr
p
?
l
2
?
h
2
16
:
95
?
4
:
3
0
:
16
2
m
Ed
x
cr
x
cr
0
:
39
?
2
2
2
0
:
16
2
16
:
95
?
0
:
39
13
:
37 kNm
=
m
2
Search WWH ::
Custom Search