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Proof ( Proof of Theorem 3 ). The proof is analogous to the former proof, but we need
to write most of the probabilistic inequalities in the different direction.
With probability at least 1
η
, the following bound on true risk holds true:
ω I )+ ln N
ln
η
R emp (
ω I )
R (
.
(30)
2 I
By joining (30) and (21) we obtain, with probability at least 1
2
η
the system of in-
equalities:
ln N
ln
η
R emp (
R emp (
ω I )
R (
ω I )
ω I )
2 I
+
η
2 I
ln
. (31)
) n :
After n independent folds we obtain, with probability at least ( 1
2
η
ln N
n
k = 1 R emp ( ω I , k )
1
n
η
2 I
ln
ln
η
2 I
n
k = 1 R emp ( ω I , k )
C
1
n
. (32)
Again as in the former proof, we need to relate R emp (
ω I , k ) from each fold to R emp (
ω I ) ,
but now we need the relation to be in the direction R emp (
ω I , k )
≥···
, so that we can
plug the right-hand-side of it into (32) and keep it true.
We write
ln N
ln N
ln
η
ln
η
ω I )
R emp (
ω I )
R emp (
2 I
2 I
R emp (
ω I ) . (33)
Reading it from the right-hand-side: the second is a (13)-like inequality but for discrete
measures, which is true with probability at least 1
η
, and the first inequality is true
with probability 1 by definition of
ω I .
 
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