Civil Engineering Reference
In-Depth Information
y 2 ) 2
4 ( y 2 ) 2 and the bolt tension
For the connection in Figure 9.19, I b =
4 ( y 1 +
+
on the most highly stressed bolt,
σ t (bolt farthest from the neutral axis of the bolt
group), is
Peh b i
A b I b =
Pe( y 1 +
y 2 )
σ t =
4 ( y 1 +
( y 2 ) 2 A b
.
y 2 ) 2
+
If y
Pe/ 10 yA b . Prying action effects, which will increase the
bolt tension, must also be considered in the connection design (e.g., by using
Equation 9.38).
=
y 1 =
y 2 ,
σ t =
9.3.4.3.1.3 Combined Shear and Tension The bolts in Figure 9.19 are subject
to shear force, F bv = τ b A b , and tensile force, T B =
T Q , which must be com-
bined to determine the allowable stress in the bolts of the connection. The allowable
shear stress for combined shear and tension in a slip-resistant connection is (from
Equation 9.45)
T
+
f bv 1
,
F bv
A b
(T B )
(T bP )
f bv =
(9.55)
where f bv
is the allowable bolt shear stress for slip-resistant connections,
T B =
T Q is the total bolt tensile force, T bP is the bolt pretension (see Equation
9.17 and Table 9.3) , and A b is the nominal area or bolt.
T
+
Example 9.5
Review the design of the slip-resistant single shear plane connection shown
in Figure 9.19 using 7/8 in. diameter A325 bolts for a load, P
=
55 kips with
eccentricity, e
=
6 in. The steel is ASTM A709 Grade 50 with F y =
50 ksi and
F u =
65 ksi. The connection geometry is similar to Figure 9.19 with:
y
=
y 1 =
y 2 =
4.0 in.
4.5 in.
w b i =
=
x
4.0 in.
a
=
1.5 in. (see Figure 9.14)
b
=
4.25 in.
t p =
0.5 in.
n b =
10 (number of bolts)
n s =
1
Shear
P
n s n b A b =
55
( 1 ) 10 ( 0.60 ) =
τ bv =
9.2 ksi
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