Civil Engineering Reference
In-Depth Information
r y
0.2 b ( radius of gyration in the lateral direction on the
compression side of the neutral axis ) ,
(7.14)
h
d ,
(7.15)
E
G
=
) =
0.38 E .
(7.16)
2 ( 1
+ υ
Substitution of Equations 7.9 through 7.16 into Equation 7.8 yields
15.4 E
(L/r y ) 2
2
0.67 E
Ld/bt f
2
,
f cr =
+
(7.17)
where f cr =
M cr /S x is the critical lateral-torsional buckling stress.
The first term in Equation 7.17 represents the warping torsion effects and the
secondtermdescribesthepuretorsioneffects.Fortorsionallystrongsections(shallow
sections with thick flanges) the warping effects are negligible and
0.67 E
Ld / bt f
0.21
0 .24
.
E
Ld / bt f
π
π
E
f cr =
=
=
Ld( 1
(7.18)
+ υ
)/bt f
For torsionally weak sections (deep sections with thin flanges and web, typical of
railway plate girders) the pure torsion effects are negligible and
1.56
,
15.4 E
(L / r y ) 2
2 E
(L/r y ) 2
π
f
cr =
=
(7.19)
which is analogous to determining the elastic (Euler) column strength of the flanges.
Using a factor of safety of 9 / 5
1.80, Equations 7.18 and 7.19 for torsionally
strong and weak sections, respectively, are
=
0.13
f cr
π E
F cr =
1.80 =
Ld( 1
(7.20)
+ υ )/bt f
and
0.87
.
f
cr
2 E
(L / r y ) 2
π
F cr =
1.80 =
(7.21)
However, due to residual stress, unintended load eccentricity, and fabrication
imperfections, axial compression member strength is based on an inelastic buck-
ling strength parabola when F cr
F y /2 and an Euler (elastic) buckling curve for
F cr
F y /2 (Figure 7.3, also see Chapter 6 on axial compression member behavior).
When F cr =
( 0.55 F y )/ 2, Equation 7.21 (elastic buckling curve) is equal and tan-
gent to the inelastic buckling strength parabola (transition curve). From Equation 7.21
the slenderness, L / r y ,at ( 0.55 F y )/ 2is
5.55 E
F y
L
r y =
.
(7.22)
 
Search WWH ::




Custom Search