Civil Engineering Reference
In-Depth Information
17,500
F
y
E
3
/
2
KL
r
min
0.166
KL
r
min
F
all
=
0.60
F
y
−
=
30
−
=
30
−
7.5
=
22.5 ksi
P
all
=
F
all
(A)
=
22.5
(
25.6
)
=
576
≥
550 kips OK.
If the effects of shear deformation are included (Equations 6.43 and 6.51b),
1
1
(L/r)
2
c
3
3.71
3.71
(
60.4
)
2
18
(
3.89
)
2
8
3
α =
+
=
+
=
1.00
l
p
r
2
P
all
α
576
1.00
=
P
all
=
=
576
≥
550 kips OK.
2
Check design of (1/2) in. cover plates with 4 in.
×
8 in. perforations at 18 in.
center-to-center spacing as shown in
Figure E6.7.
The properties of half the member at the center of the perforation about
its own axis are (see
Figure E6.8)
:
2
(
4
)(
0.5
)(
4
)
+
8.82
(
3.67
)
2
(
4
)(
0.5
)
+
z
=
=
3.77 in.
8.82
12.82 in.
2
A
pc
=
2
(
4
)(
0.5
)
+
8.82
=
3.67
)
2
2
(
0.5
)(
4
)
3
/
12
3.77
)
2
I
pc
=
5.14
+
8.82
(
3.77
−
+
+
2
(
4
)(
0.5
)(
4
−
10.77 in.
4
=
10.77
12.82
=
r
pc
=
0.92 in.
8
0.92
=
C
pc
=
8.7
≤
20 OK
1
3
(
60.4
)
≤
L
3
r
≤
C
pc
=
8.7
≤
20.1 OK
c
=
8
≤
2
w
perf
≤
2
(
4
)
≤
8 in. OK
b
≤
9 in. OK (
b
is the width between the
c
=
8
≤
l
p
−
18
−
9
≤
inside lines of fasteners)
b
50
≥
9
50
≥
t
pc
≥
0.18 in. OK
w
perf
)
F
y
4
)
F
y
t
pc
≥
1.17
(b
−
E
≥
1.17
(
9
−
E
≥
0.24 in. OK
