Civil Engineering Reference
In-Depth Information
P L
C
D
B
A
h p
( h e + h p )/2
V e
V e
P e
b t
P e
FIGURE E5.14 Triangular portal frame.
Example 5.15
The forces in the end portal bracing system (Figure E5.15) of the through truss
span in Example 5.10 are required.
h e =
33.5 ft (in-plane height of the portal)
h p =
8.5 ft (in-plane height of the portal bracing system)
20.0 (spacing of trusses)
P L = ( 6 ) 19.55 ( 0.35 )/ 2
b t =
20.4 kips (top lateral truss wind force reactions
transferred to the end portal frame)
R e =
=
20.4
[ ( 42.0 )/ 2
] / 20
=
21.4 kips (additional compression in the end post
due to portal action)
P L
C
D
8.5'
B
A
5.0'
33.5'
M e
M e
H e
H e
R e
20.0'
R e
FIGURE E5.15 Braced triangular portal frame.
 
 
Search WWH ::




Custom Search