Civil Engineering Reference
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d
= ( 25 / 30 ) 15
=
12.50
e
=
60 / 4
=
15.00
f
= ( 21 / 30 ) 15
=
10.50
g
= ( 16 / 30 ) 15
=
8.00
= ( 10 / 30 ) 15
=
5.00
h
i
= ( 5 / 30 ) 15
=
2.50
M C =
20 ( 3.50 ) +
40 ( 7.50
+
10.00
+
12.50
+
15.00 )
+
26 ( 10.50
+
8.00
+
5.00
+
2.50 ) =
2546 ft-kips.
Example 5.4
Determine the bending moment per rail at location C under axle NP
3of
the Cooper's E80 load on a 60 ft long through plate girder span with a floor
system comprising floorbeams and 20 ft long stringers.
The influence line for bending moments at location C is shown in
Figure E5.4.
The ordinates of the influence lines are
=
a
= ( 7 / 20 ) 13.33
=
4.67
b
= ( 15 / 20 ) 13.33
=
10.00
5′
6′
8
5
5
9
5
5′
40 k
40 k
40 k
40 k
20 k
26 k
26 k
26 k
26 k
c
d
e
b
f
h
a
i
g
C
13
B
A
5
20
30′
30′
FIGURE E5.4
 
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