Civil Engineering Reference
In-Depth Information
With
NP
=
4 (Cooper's load configuration wheel number 4)
From
Table 5.1:
x
1
=
(S
1
)
4
=
18 ft
since
x
1
≤
L/
2
≤
30 ft; N1
=
1
support B is 30
+
18
=
48 ft from N1
since
(S
1
)
9
=
48 ft,
NL
=
9 and is over support B
0
NE
is the last wheel on the span and is equal to
NL
=
xL
−
1
=
8 when
NL
is over
support B
M
B
L
M
8,1
+
P
1,8
(xL)
60
6992
+
258
(
0
)
60
R
B
=
=
=
=
116.5 kips,
R
B
L
2
−
M
3,1
=
M
C
=
116.5
(
30
)
−
960
=
2536 ft-kips.
With
NP
=
5 (Cooper's load configuration wheel number 5)
From Table 5.1:
x
1
=
(S
1
)
4
=
23 ft
since
x
1
≤
L/
2
≤
30 ft; N1
=
1
support B is 30
+
23
=
53 ft from N1
since
(S
1
)
9
=
5 ft from support B
NE
is the last wheel on the span and is equal to
NL
48 ft,
NL
=
9 and is
xL
=
53-48
=
=
9 when
NL
is not over
support B
M
8,1
+
P
1,9
(xL)
60
M
B
L
6992
+
284
(
5
)
60
R
B
=
=
=
=
140.2 kips,
R
B
L
2
−
M
4,1
=
M
C
=
140.2
(
30
)
−
1660
=
2546 ft-kips.
With
NP
=
12 (Cooper's load configuration wheel number 12)
From
Table 5.1:
With
NP
=
12, the first wheel on the span
=
N1
=
8
x
1
=
(S
1
)
12
−
(S
1
)
8
=
69
−
43
=
26 ft
support B is 30
+
26
=
56 ft from N1
=
8
With
NP
=
12, the last wheel on the span is
NL
=
17
xL
=
(L/
2
)
−[
(S
1
)
17
−
(S
1
)
12
]=
30
−
(
99
−
69
)
=
0 ft and N17 is over
support B
NE
is the last wheel on the span and is equal to
NL
−
1
=
16 when
NL
is
over support B
M
16,8
+
P
8,16
(xL)
60
M
B
L
8480
+
(
336
−
78
)(
0
)
R
B
=
=
=
=
141.3 kips,
60
R
B
L
2
−
M
11,8
=
M
C
=
141.3
(
30
)
−
1682
=
2558 ft-kips.
