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where S k is a unitary mode matrix of dimensions N k ×
N k , spanning the column space
of
the
matrix
T (k)
obtained
from
the
mode-n
flattening
of T ;
…… Z is a core tensor of the same dimensions as T , which satisfies
the following conditions [16]:
1. Two subtensors
NN N N N
××
×
×
∈ℜ
1
2
m
n
P
Z and
Z , obtained by fixing the n k index to a , or b ,
k na
=
k nb
=
are orthogonal, i.e.
ZZ ,
=
0
(2)
na nb
=
=
k
k
for all possible values of k for which a
b .
2. All subtensors can be ordered according to their Frobenius norms
ZZ Z ,
0
(3)
n
=
1
n
=
2
n N
=
k
k
k
P
for all k .
The following Frobenius norm
k
na a
Z
=
σ
(4)
=
k
is called the a-mode singular value of T . Each i-th vector of the matrix S k is the i-th k-
mode singular vector.
Assuming decomposition (1) of a tensor T , singular values (4) provide a notion of an
energy of this tensor in the terms of the Frobenius norm, as follows
R
R
()
( )
2
1
2
P
2
2
1
P
T
=
σ
=
=
σ
=
Z ,
(5)
a
a
a
a
=
1
=
1
where R k denotes a k-mode rank of T .
The SVD decomposition allows representation of a matrix as a sum of rank one
matrices. The summation spans number of elements, however no more than a rank of
the decomposed matrix. Similarly to the SVD decomposition of matrices, based on
the decomposition (1), a tensor can be represented as the following sum
N
P
s
T
=
T
h
hPP
×
,
(6)
h
=
1
where
TZ
=× ×
SS S
×
,
(7)
h
1122 1 1
P
P
denotes the basis tensors and s h P are columns of the unitary matrix S P . Since T h is of
dimension P -1 then
P in (6) is an outer product, i.e. a product of two tensors of
dimensions P -1 and 1 . The result is a tensor of dimension P , i.e. the same as of T .
Fig. 2 depicts a visualization of this decomposition for a 3D tensor. In this case T h
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