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In-Depth Information
h
h
β
r uu
=
-- -----------------
-- -----------------
(
h
tan
β k
–
D n
cos
)
+
(12.130)
r
cos 3
β k
r 2
cos
β k
1
--------------
β
h
+
2
tan
β k
sin
β k
–
2
sin
β k
D n
cos
cos
β k
3
r 3
1
r 2
 hD n
 hD n
β
β
-- - 
-- - 
) 2
r ô ô ô
=
(
+
sin
)
(
+
sin
–
1
(12.131)
h
–
r 2
3
- -- --  hD n
β
β
r ô ô u
=
-- -------------------
(
h
tan
β k
–
D n
cos
)
(
+
sin
) 2
+
1
(12.132)
r 3
cos 2
β k
hv
tan
r 3
β k
β
-------- - -----------
r ô st
=
(
hD n
+
sin
)
(12.133)
 h 2
–
r 5
3
β
β
- -- -- 
----------------
r ô uu
=
(
hD n
+
sin
) h
(
tan
β k
–
D n
cos
)
(12.134)
cos 4
β k
–
r 3
1
 h
β
β
- -- -- 
r ô ss
=
(
tan
β k
–
D n
cos
) hD n
(
+
sin
)
(12.135)
h
1
r 2
 h
β
β
-- -----------------
-- - 
r uss
=
(
D n
cos
)
(
tan
β k
–
D n
cos
) h
(
tan
β k
)
+
1
(12.136)
r
cos 2
β k
–
r 3
h
tan
β k
β
-- -------------------
r stu
=
(
h
tan
β k
–
D n
cos
)
(12.137)
cos 2
β k
β
hD n
cos
h
tan
r 2
β k
β
-------------------------
------ -- ---------
r suu
=
(
h
tan
β k
–
D n
cos
)
+
1
(12.138)
r
cos 2
β k
v 2 h
-- -------------------
β
r ô tt
=
(
h
tan
β k
–
D n
cos
)
(12.139)
r 3
cos 2
β k
r uuu
=
(12.140)
h
β
β
-- -----------------
[
8 h
tan
β k
+
sin 2
β k
(
hD n
–
cos
)
–
2 D n
cos
]
+
r
cos 4
β k
3 h 2
3 h 2
β
β
-- -------------------
-- -------------------
(
h
tan
β k
–
D n
cos
)
+
(
h
tan
β k
–
D n
cos
)
r 3
cos 5
β k
r 3
cos 5
β k
3 h 3
1
β
-- -------------------
β
-----------------
+
(
h
tan
β k
–
D n
cos
)
+
(
h
tan
β k
–
D n
cos
)
2
cos
β k
r 5
cos 6
β k
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