Graphics Programs Reference
In-Depth Information
p
a ó
R i
=
r
–
i
(
x i
,,
y i
z i
)
a ó
a ó
r
a ó
r i
R 1
=
r
–
θ
1
(
000
,,
)
a ó
a ó
a ó
θ 1
r 1
a ó
a ó
(
x 1
,
y 1
,
z 1
)
Figure 8.3 Geometry for an array antenna.
x i 2
y i 2
z i 2
(
++
)
r i
r 2
--------------------------------
=
------
«
1
(8.20)
r 2
Thus, a good approximation (using binomial expansion) for Eq. (8.19) is
R i
=
r – x i θφ
(
sin
cos
+
y i θφ
sin
sin
+
z i
cos
θ
)
(8.21)
It follows that the phase contribution at the far field point from the
ith
radiator
with respect to the phase reference is
–
jkR i
e jk x i θφ
(
sin
cos
+
y i θφ
sin
sin
+
z i
cos
θ
)
–
jkr
e
=
e
(8.22)
Remember, however, that the unit vector
r 0
along the vector
r
is
r
r
ó x θφ
ó y θφ
ó z
r 0
==
- -- --
sin
cos
+
sin
sin
+
cos
θ
(8.23)
Hence, we can rewrite Eq. (8.22) as
–
jkR i
e j Ψ i θφ
(
,
)
e jk r i
(
r 0
)
–
jkr
–
jkr
e
=
e
=
e
(8.24)
Finally, by virtue of superposition, the total electric field is
N
I i e j Ψ i θφ
(
,
)
E θφ
(
,
)
=
(8.25)
i
=
1
which is known as the array factor for an array antenna where the complex cur-
rent for the
ith
element is
I i
.
 
Search WWH ::




Custom Search