Hardware Reference
In-Depth Information
SOLUTIONS FOR CHAPTER 7
7.1
Applying Equation (7.19), we can verify that
i
C k
T k
+ B i
i (2 1 /i
i, 1
i
n,
T i
1) .
k =1
So we have
C 1 + B 1
T 1
9
10 < 1
=
C 1
T 1
+ C 2 + B 2
T 2
4
10 +
6
15 =0 . 8 < 0 . 83
=
C 1
T 1
+ C 2
T 2
+ C 3
T 3
4
10 +
3
15 +
4
20 =0 . 8 > 0 . 78 .
=
Being condition (7.19) only sufficient, we cannot conclude anything about fea-
sibility. By applying the response time analysis we have to verify that
i, 1
i
n,
R i
D i
where
R i
T k
C k .
i− 1
R i
= C i + B i +
k =1
So we have
R 1
=
C 1 + B 1 =9 < 10
R (0)
2
=
C 1 + C 2 + B 2 =10
C 2 + B 2 + 10
10
4=10 < 15
R (1)
2
=
R (0)
3
=
C 1 + C 2 + C 3 =11
C 3 + 11
10
4+ 11
15
3=15
R (1)
3
=
C 3 + 15
10
4+ 15
15
3=15 < 20 .
R (2)
3
=
Hence, we can conclude that the task set is schedulable by RM.
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