Hardware Reference
In-Depth Information
By summing equations (9.29) we have
n
1
k i
L d = L 0
F
.
i =1
Thus, force F can be expressed as
F = K p ( L 0
L d ) ,
(9.30)
where
1
i =1
K p =
.
(9.31)
1
k i
Substituting expression (9.30) into Equation (9.29) we finally achieve
L d ) K p
k i
ix i = x i 0
( L 0
.
(9.32)
Equation (9.32) allows us to compute how each spring has to be compressed in order
to have a desired total length L d .
For a set of elastic tasks, Equation (9.32) can be translated as follows:
U d ) E i
E 0
iU i = U i 0
( U 0
.
(9.33)
where E i =1 /k i and E 0 = i =1 E i .
INTRODUCING LENGTH CONSTRAINTS
If each spring has a length constraint, in the sense that its length cannot be less than a
minimum value x i min , then the problem of finding the values x i requires an iterative
solution. In fact, if during compression one or more springs reach their minimum
length, the additional compression force will only deform the remaining springs. Such
a situation is depicted in Figure 9.28.
Thus, at each instant, the set Γ can be divided into two subsets: a set Γ f of fixed springs
having minimum length, and a set Γ v of variable springs that can still be compressed.
Applying Equations (9.32) to the set Γ v
of variable springs, we have
L d + L f ) K v
k i
S i
Γ v
x i = x i 0
( L v 0
(9.34)
where
L v 0 =
S i Γ v
x i 0
(9.35)
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