Hardware Reference
In-Depth Information
The resulting utilization is then
C s
T s
+ C 1
T 1
+ ... + C n
T n
U
=
=
U s + T 2
T 1
+ ... + T n
T n− 1
T n− 1
+ 2 T s
T n
=
=
T 1
T n
+ 2 T s
T 1
T 1
T n
U s + T 2
T 1
T n
T n− 1
=
+ ... +
n.
Defining
R s = T 1 /T s
R i = T i +1 /T i
K =2 T s /T 1 =2 /R s
and noting that
T n
T 1
R 1 R 2 ...R n− 1 =
,
the utilization factor may be written as
n− 1
K
R 1 R 2 ...R n− 1
U = U s +
R i +
n.
i =1
Following the approach used for RM, we minimize U over R i , i =1 ,...,n
1.
Hence,
∂U
∂R i
K
R i ( n− 1
j = i R j ) .
Thus, defining P = R 1 R 2 ...R n− 1 , U is minimum when
=1
R 1 P = K
R 2 P = K
...
R n− 1 P = K ;
that is, when all R i have the same value:
R 1 = R 2 = ... = R n− 1 = K 1 /n .
Substituting this value in U we obtain
K
K (1 1 /n )
1) K 1 /n +
U lub
U s
= n
n =
nK 1 /n
K 1 /n + K 1 /n
=
n =
n ( K 1 /n
=
1);
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