Hardware Reference
In-Depth Information
The resulting utilization is then
C
s
T
s
+
C
1
T
1
+
...
+
C
n
T
n
U
=
=
U
s
+
T
2
−
T
1
+
...
+
T
n
−
T
n−
1
T
n−
1
+
2
T
s
−
T
n
=
=
T
1
T
n
+
2
T
s
T
1
T
1
T
n
−
U
s
+
T
2
T
1
T
n
T
n−
1
=
+
...
+
n.
Defining
⎧
⎨
R
s
=
T
1
/T
s
R
i
=
T
i
+1
/T
i
K
=2
T
s
/T
1
=2
/R
s
⎩
and noting that
T
n
T
1
R
1
R
2
...R
n−
1
=
,
the utilization factor may be written as
n−
1
K
R
1
R
2
...R
n−
1
−
U
=
U
s
+
R
i
+
n.
i
=1
Following the approach used for RM, we minimize
U
over
R
i
,
i
=1
,...,n
−
1.
Hence,
∂U
∂R
i
K
R
i
(
n−
1
j
=
i
R
j
)
.
Thus, defining
P
=
R
1
R
2
...R
n−
1
,
U
is minimum when
⎧
⎨
=1
−
R
1
P
=
K
R
2
P
=
K
...
R
n−
1
P
=
K
;
⎩
that is, when all
R
i
have the same value:
R
1
=
R
2
=
...
=
R
n−
1
=
K
1
/n
.
Substituting this value in
U
we obtain
K
K
(1
−
1
/n
)
−
1)
K
1
/n
+
U
lub
−
U
s
=
n
−
n
=
nK
1
/n
K
1
/n
+
K
1
/n
=
−
−
n
=
n
(
K
1
/n
=
−
1);
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