Java Reference
In-Depth Information
import java.nio.file.*;
import java.io.IOException;
public class ListDirectoryContents {
public static void main(String[] args) {
Path currentPath = Paths.get(System.getProperty("user.dir"));
currentPath = currentPath.getParent();
// Get the entire directory contents
filterDirectoryContents(currentPath, null);
// Now try a filter for .txt files
System.out.println("\nFilter for .txt:");
filterDirectoryContents(currentPath, "*.txt");
// Get files with a 3 character extension begiining with 'j'
System.out.println("\nFilter for .j??:");
filterDirectoryContents(currentPath, "*.j??");
}
// Filter the contents of a directory
private static void filterDirectoryContents(Path path, String
filter) {
try (DirectoryStream<Path> paths =
filter != null ? Files.newDirectoryStream(path,
filter):
Files.newDirectoryStream(path)){
System.out.println("\n" + path + " directory contains:");
for(Path p : paths) {
System.out.println(" " + p.getFileName() +
(Files.isDirectory(p) ? " is a
directory." : ""));
}
} catch(NotDirectoryException e) {
System.err.println("Path is not a directory." + e);
} catch(IOException e) {
System.err.println("I/O error." + e);
}
}
}
ListDirectoryContents.java
I have engineered the directory path to be one containing a variety of files and directories to get some
interesting output. You need to choose a path that references an interesting directory on your computer
and adjust the filter strings accordingly. On my system I get the following output:
