Exceptions - Beginning Java - page 361

Execution of the try block stops at the point where the exception occurs, and the code in the catch block
for the exception is executed immediately. If there is a return statement in the catch block, this isn't ex-
ecuted until after the finally block has been executed. As I discussed earlier, if a return statement that
returns a value is executed within a finally block, that value is returned, not the value from any previous
return statement.
If an exception is thrown in a finally block, this will terminate the execution of the code in the finally
block and the method. You can see the effect if you add the following statement to the finally block in
divide() :
int result = array[index]/array[index+1];
When ArithmeticException is thrown in the try block, the same exception is thrown in the finally
block as a result of this statement. You will see from the output that the divide() method terminates and
the exception is caught in main() . Try moving the statement to the catch block for ArithmeticException .
You'll see that the finally block still executes even though an exception is thrown in the catch block.
Execution When an Exception Is Not Caught
The next block of output is a consequence of the third call to the divide() method:
First try block in divide() entered
Index-out-of-bounds exception caught in divide()
array length = 3 index = 1
finally block in divide()
Executing code after try block in divide()
Index-out-of-bounds exception caught in main()
Outside first try block in main()