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x B ¼
p
˃
ð
14
:
9
Þ
x A þ
py A ¼
1
ð
14
:
10
Þ
x B þ
py B ¼
p
ð
14
:
11
Þ
x A þ
x B ¼
1
ð
14
:
12
Þ
y A þ
y B ¼
1
ð
14
:
13
Þ
one of the equations being redundant. The solutions are then:
x A o
¼ ˁ
ð
14
:
14
Þ
x B o
ˁ
ð
:
Þ
¼
1
14
15
y A o
¼ ˃
ð
14
:
16
Þ
y B o
¼
1
˃
ð
14
:
17
Þ
¼ ˃ 1
x B o
y A o
p
ð
1
ˁ
Þ
=
> < 1
ð
14
:
18
Þ
provided they lie on the feasible domain; the “price” is clearly only equal to one if
˃ ¼
, which was already hinted at in the discussion of the first solution concept.
The new variable p plays indeed the role of an exchange rate of y for x ; for instance
p
1
ρ
1 implies that A exchanges more units of x than he would receive units of y .This
reminiscence of a Walrasian “umpire' leads up to the possible role of a third “good
offices” body, persuading (in the case studied, A ) to accept the “price” given the
relative preferences of A and B .
A mixed linear non-linear solution is also possible, but the solution, as in the
double linear preference function case, is analytically less tractable.
It has already be said about the Cobb-Douglas specification that (1,0)-(0,1)
solutions are excluded as a result of maximising behaviour, even asymptotically,
as “inferior” isoquants are nearer to the axes than 'superior” ones, without any of
them ever cutting those axes. A modified specification might include the extreme
points, e.g.:
>
1 ˁ
Þ ˁ y A þ ʸ
ˆ A ¼
ð
x A þ
q
ð
Þ
ð
14
:
19
Þ
giving as “diagonal” optimal values:
Þ 1
x A o
ˁ ʸ
ð
1
þ
2
ʸ
!
¼
0, y A ¼
1
ð
14
:
20a
Þ
1
1
1
1
Þ 1
ʸ
ð
1
þ
2
ʸ
< ˁ <
þ ʸ
þ
2
ʸ
!
x A o
¼
þ
2
ʸ
ˁ ʸ
Þ 1 ˁ ʸ
ð
y A o
¼
ð
1 þ 2 ʸ
14
:
20b
Þ
Þ 1
x A o
1, y A o
ˁ
ð
1
þ ʸ
Þ
ð
1
þ
2
ʸ
!
¼
¼
0
ð
14
:
20c
Þ
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