Exception Handling - Absolute Java - page 542

Display 9.5 Using a Programmer-Dei ned Exception Class (part 2 of 3)

13 if (denominator == 0)

14 throw new DivisionByZeroException();

15 double quotient = numerator/( double )denominator;
16 System.out.println(numerator + "/"
17 + denominator
18 + " = " + quotient);
19 }
20 catch (DivisionByZeroException e)
21 {
22 System.out.println(e.getMessage());
23 secondChance();
24 }

25 System.out.println("End of program.");
26 }

27 public static void secondChance()
28 {
29 Scanner keyboard = new Scanner(System.in);
30 System.out.println("Try again:");
31 System.out.println("Enter numerator:");
32 int numerator = keyboard.nextInt();
33 System.out.println("Enter denominator:");
34 System.out.println("Be sure the denominator is not zero.");
35

int denominator = keyboard.nextInt();

36
37 if (denominator == 0)
38 {
39 System.out.println("I cannot do division by zero.");
40 System.out.println("Aborting program.");
41 System.exit(0);
42 }

Sometimes it is better to handle
an exceptional case without throwing
an exception.

43 double quotient = (( double )numerator)/denominator;
44 System.out.println(numerator + "/"
45

+ denominator

46 + " = " + quotient);

47 }
48 }