Graphics Programs Reference
In-Depth Information
EXAMPLE A4
Letting
123
121
0 12
1
6
8
0
A
=
u
=
v
=
2
3
v , Av and u T Av .
compute u
+
v , u
·
Solution
=
1
+
8
9
6
u
+
v
=
6
+
0
2
3
5
u
·
v
=
1(8))
+
6(0)
+
(
2)(
3)
=
14
=
=
a 1 ·
v
a 2 ·
1(8)
+
2(0)
+
3(
3)
1
5
Av
=
v
a 3 ·
1(8)
+
2(0)
+
1(
3)
+
+
v
0(8)
1(0)
2(
3)
6
u T Av
=
·
=
+
+
=
u
( Av )
1(
1)
6(5)
(
2)(
6)
41
EXAMPLE A5
Compute
|
A
|
, where A is given in Example A4. Is A positive definite?
Solution Laplace's development of the determinanton the first rowyields
1
2
+
3
21
12
11
0 2
12
0 1
|
A
| =
=
1(3)
2(2)
+
3(1)
=
2
Developmenton the third rowissomewhateasierdue to the presence of the zero
element:
0
1
+
2
23
21
13
11
12
12
|
A
| =
=
0(
4)
1(
2)
+
2(0)
=
2
To verifypositive definiteness, weevaluate the determinants of the leading
minors:
A 11 =
1
>
0O.K.
=
=
A 11 A 12
A 21 A 22
12
12
0
Not O.K.
A is not positive definite.
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