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which yieldsfor the Jacobian matrix
=
x
∂ξ
y
∂ξ
1
+ η
4
1
J (
ξ,η
)
=
x
∂η
y
∂η
5
+ ξ
4
0
Thus the area scale factoris
+ ξ
4
Nowwecan map the integralfrom the quadrilateral to the standard rectangle.Refer-
ring to Eq. (6.45), weobtain
5
|
ξ,η
| =
J (
)
1
1
(1
5
(5
+ ξ
)(1
+ η
)
+ ξ
4
) 2
I
=
+ ξ
+
d
ξ
d
η
4
1
1
1
1
45
16 +
d
21
8 ξ +
29
16 ξ
1
4 ξ
25
16 η +
5
8 ξη +
1
16 ξ
2
3
2
=
+
+
η
ξ
d
η
1
1
Noting thatonly evenpowersof
ξ
and
η
contribute to the integral, wecan simplify the
integralto
1
1
45
16 +
2 d
29
16 ξ
41
3
I
=
ξ
d
η =
1
1
EXAMPLE 6.14
Evaluate the integral
1
1
cos π
x
2
cos π
y
2
dx dy
1
1
by Gauss-Legendrequadratureoforder three.
Solution From the quadratureformulainEq. (6.40), wehave
3
3
A i A j cos π
cos π
x i
2
y j
2
I
=
i
=
1
j
=
1
y
1
a
a
b
b
b
0
x
a
b
a
−1
−1
1
0
The integrationpoints are shown in the figure; their coordinates and the correspond-
ing weights arelistedinTable 6.3. Note that the integrand, the integrationpoints and
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